Закрепление вычислительных навыков в пределах 10.Цветик-семицветик презентация

2 – 2 =
3 – 1 =
3 – 2 + 3 =
3 + (4 – 1) =
1 + 1 =
2 – 1 =
0 + 2 =
4 – 4 + 3 =
4 – 2 + 1 =
2– (4 – 3)=
3 + 1 =
4 – 2 =
4 – 3 =
1 + 2 =
4 – 1 =
2 + 2 =
3 + 1 – 2 =
2 – 0 =
0 + 4 – 3 =
4 – (4 – 2) =
3 – 2 =
4 – (2 + 1)=
1 + 2 + 1 =

4 – 4 + 3 =
3 + 1 – 2 =
1 + 2 + 1 =
2– (4 – 3)=
4 – 2 + 1 =
4 – (4 – 2) =
0 + 4 – 3 =
3 + (4 – 1) =
4 – (2 + 1)=
3 – 2 + 3 =
2 – 1 =
1 + 1 =
3 – 1 =
3 + 1 =
4 – 2 =
4 – 3 =
1 + 2 =
4 – 1 =
2 + 2 =
3 – 2 =

2 + 2 =
4 – 2 =
4 – 4 + 3 =
3 + 1 – 2 =
1 + 2 + 1 =
2– (4 – 3)=
4 – 2 + 1 =
4 – (4 – 2) =
0 + 4 – 3 =
3 + (4 – 1) =
4 – (2 + 1)=
3 – 2 + 3 =
3 – 1 =
3 + 1 =
4 – 3 =
1 + 2 =
4 – 1 =
3 – 2 =

4 – 1 =
4 – 4 + 3 =
3 + 1 – 2 =
1 + 2 + 1 =
2– (4 – 3)=
4 – 2 + 1 =
4 – (4 – 2) =
0 + 4 – 3 =
3 + (4 – 1) =
4 – (2 + 1)=
3 – 2 + 3 =
3 – 1 =
1 + 2 =
3 – 2 =
3 + 1 =
4 – 3 =

3 – 2 =
4 – 4 + 3 =
3 + 1 – 2 =
1 + 2 + 1 =
2– (4 – 3)=
4 – 2 + 1 =
4 – (4 – 2) =
0 + 4 – 3 =
3 + (4 – 1) =
4 – (2 + 1)=
3 – 2 + 3 =
3 – 1 =
1 + 2 =

2– (4 – 3)=
4 – 2 + 1 =
4 – (4 – 2) =
0 + 4 – 3 =
3 + (4 – 1) =
4 – (2 + 1)=
3 – 2 + 3 =
4 – 4 + 3 =
3 + 1 – 2 =
1 + 2 + 1 =

1
3 + (2 – 1) =
4– (4 – 3)=
4 – (4 – 2) =
4 – (2 + 1)=
3
5
2
6
4
0

3 + (2 – 1) =
4– (4 – 3)=
4 – (4 – 2) =
3
5
2
6
0
1
4

4– (4 – 3)=
4 – (4 – 2) =
5
2
6
0
1
4
3

4 – (4 – 2) =
5
3
6
0
1
4
2

2 + 3
5 + 0
6 – 1
6 – 3
4 + 1
6 – 6
6 – 4
10 + 1
5 – 2
5 – 3
6 – 5
5 + 1
5 – 1
4 + 2
6 – 2
5 – 4
5 – 0
5 – 5
3 + 3
6 – 0
11 – 1
6 + 0
11 – 10
Составьте обратные примеры

7 – 0
5 – 2
3 + 3
0 + 7
4 + 3
7 – 2
6 – 4
7 – 6
7 – 1
7 – 7
6 + 1
2 + 5
7 – 3
4 – 2
7 – 5
7 – 4
Найдите «лишние примеры».

4 + 4 =
8 – 5 =
1 + 7 =
6 + 2 =
8 – 7 =
8 + 0 =
8 – 4 =
8 – 3 =
5 + 3 =
8 – 6 =
8 – 0 =
3 + 4 =
8 – 8 =
8 – 1 =
8 – 2 =
8
4
5
8
1
8
8
3
2
7
0
8
6
8
7

9 – 0
5 + 4
3 + 6
7 + 2
1 + 8
9 + 0
9 – 6
9 – 3
9 – 1
9 - 7
9 – 4
9 – 8
9 – 5
9 – 2
9 – 9
0
5
3
9
7
2
9
9
4
8
9
9
1
6
9

10 – 1=
10 – 5=
10 – 9=
10 – 6=
10 – 8=
0 + 10=
7 + 3 =
4 + 6=
10 – 7=
10 – 2=
5 + 5 =
8 + 2 =
10– 4=
10 – 3=
1 + 9 =
10
2
1
10–10=
10
8
4
10
3
6
10
10
0
5
7
10
9

3 – 2
7 – 5
5 + 5
1 + 8
4 + 4
9 – 5
6 – 1
9 – 3
8 – 5
2 + 7
10 – 3
10–6+3=
3+7–6=
8- 4+5=
5+2+3=
9–7+6=
9–(7–2)=
10-(6+3)=
4+(7–5 )=
3+(2+5)=
8–(10–4)=
Решите круговые примеры