Dividing polynomials презентация

Содержание

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Lecture Outline

Lecture Outline

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Introduction

 

Introduction

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1.4.1 Divide a polynomial by another polynomial using long division

Dividing polynomials is

much like the familiar process of dividing numbers. When we divide 38 by 7, the quotient is 5 and the remainder is 3.
We write 38 = 7 x 5 + 3
or, alternatively,

1.4.1 Divide a polynomial by another polynomial using long division Dividing polynomials is

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1.4.1 Divide a polynomial by another polynomial using long division

! The word

‘remainder’ is pronounced as [rɪˈmeɪn.dər]

1.4.1 Divide a polynomial by another polynomial using long division ! The word

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cont’d

 

 

 

 

 

 

 

 

cont’d

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We repeat the process using the last line –2x + 12 as the

dividend.

 

 

 

 

 

 

 

 

 

4

 

We repeat the process using the last line –2x + 12 as the dividend. 4

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The division process ends when the last line is of lesser degree than

the divisor. The last line then contains the remainder, and the top line contains the quotient.
The result of the division can be interpreted in either of two ways:
or

cont’d

The division process ends when the last line is of lesser degree than

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Solution

Solution

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1.4.2 Divide a polynomial by a linear polynomial using synthetic division

1.4.2 Divide a polynomial by a linear polynomial using synthetic division

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We will bring down the 2, multiply 3 ● 2 = 6, and

write the result in the middle row. Then we add.

We will bring down the 2, multiply 3 ● 2 = 6, and

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cont’d

Multiply: 3 ● 2 = 6

Add: –7 + 6 = –1

We repeat this

process of multiplying and then adding until the table is complete.

Multiply: 3(–1) = –3

Add: 0 + (–3) = –3

2 -7 0 5

3

2

6

-1

-3

-3

cont’d Multiply: 3 ● 2 = 6 Add: –7 + 6 = –1

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cont’d

 

cont’d

Multiply: 3(–3) = –9

Add: 5 + (–9) = –4

2 -7 0 5

3

2

6

-1

-3

-3

-9

-4

cont’d cont’d Multiply: 3(–3) = –9 Add: 5 + (–9) = –4 2

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cont’d

 

 

 

cont’d

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1.4.3 Apply the factor theorem to factorize polynomials

The next theorem says that zeros

of polynomials correspond to factors.

 

 

1.4.3 Apply the factor theorem to factorize polynomials The next theorem says that

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cont’d

 

 

cont’d

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cont’d

Using synthetic or long division, as shown below:

cont’d

 

cont’d Using synthetic or long division, as shown below: cont’d

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cont’d

 

Given polynomial

Using synthetic
or long division

Factor quadratic x2 + x – 6

cont’d Given polynomial Using synthetic or long division Factor quadratic x2 + x – 6

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cont’d

 

 

cont’d

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cont’d

 

cont’d

 

cont’d cont’d

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Solution

 

Solution

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cont’d

You can use the remainder theorem to find the remainder value:

1.4.4 Apply the

remainder theorem to find the remainder

 

cont’d You can use the remainder theorem to find the remainder value: 1.4.4

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cont’d

 

cont’d

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cont’d

 

1 -1 1 5

-1

1

-1

-2

2

3

-3

2

 

cont’d 1 -1 1 5 -1 1 -1 -2 2 3 -3 2

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cont’d

 

cont’d

cont’d cont’d

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cont’d

 

 

Solution

cont’d Solution

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cont’d

 

cont’d

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cont’d

 

cont’d

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cont’d

Based on the previous exercise, we can state the following:

Remainder Theorem – version

2

cont’d Based on the previous exercise, we can state the following: Remainder Theorem – version 2

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Solution

 

 

Solution

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Your turn!

 

Your turn!

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1.4.5 Identify the real root composition from the graph of a cubic polynomial
The

graphs of polynomials of degree 0 and 1 are lines, and the graphs of polynomials of degree 2 are parabolas. The greater the degree of a polynomial, the more complicated the graph can be. However, the graph of a polynomial is continuous. This means the graph has no breaks or holes.
Moreover, the graph of a polynomial function is a smooth curve, that is, it has no corners or sharp points.

1.4.5 Identify the real root composition from the graph of a cubic polynomial

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1.4.5 Identify the real root composition from the graph of a cubic polynomial
In

this lecture we want to explore how the zeros of a cubic polynomial and their multiplicity affect the shape of the graph. In the next lecture you will learn basics of sketching a cubic polynomial.

1.4.5 Identify the real root composition from the graph of a cubic polynomial

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Case A: p(x) has a triple zero

 

 

 

 

 

k>0

 

 

 

 

k<0

Case A: p(x) has a triple zero k>0 k

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Case B: p(x) has a double zero

 

 

 

 

 

 

k>0

 

 

 

 

 

k<0

Case B: p(x) has a double zero k>0 k

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Case C: p(x) has three linear distinct factors

 

 

 

 

 

 

 

k>0

 

 

 

 

 

 

k<0

Case C: p(x) has three linear distinct factors k>0 k

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Case D: p(x) has an irreducible quadratic factor

 

 

 

 

 

k>0

 

 

 

 

k<0

Does not have real zeros

Case D: p(x) has an irreducible quadratic factor k>0 k Does not have real zeros

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Your turn!

Match the cubic function with one of the graphs shown.

 

x

y

x

y

x

y

x

y

I

II

III

IV

V

Your turn! Match the cubic function with one of the graphs shown. x

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1 -3 5/2 -1

2

1

2

-1

-2

1/2

1

0

 

1 -3 5/2 -1 2 1 2 -1 -2 1/2 1 0

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Learning outcomes

1.4.1 Divide a polynomial by another polynomial using long division
1.4.2 Divide

a polynomial by a linear polynomial using synthetic division
1.4.3 Apply the factor theorem to factorize polynomials
1.4.4 Apply the remainder theorem to find the remainder
1.4.5 Identify the real root composition from the graph of a cubic polynomial

Learning outcomes 1.4.1 Divide a polynomial by another polynomial using long division 1.4.2

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Formulae

 

 

Formulae

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